I use a combined strategy based on strength, volume change, volatility (ATR), and support/resistance levels (S1/R1).
The data comes from a CSV export of Stein Investments indicators: FX Power, FX Volume, FX Dynamic, FX Levels.

Column Description:
- Symbol: Forex symbol
- Delta FXP (3 analysis periods): Strength difference (Base - Quote)
  (Each strength value ranges from -50 to +50)
- Base Net Long Change: % change in net long positions of the base currency
- Quote Net Long Change: % change in net long positions of the quote currency
- Net Long Change Delta: Difference in net long changes (Base - Quote)
- Base Volume Change: % change in total trading volume of the base currency
- Quote Volume Change: % change in total trading volume of the quote currency
- Total Volume Change Delta: Difference in total volume changes (Base - Quote)
- ATR (%): Volatility filter (current ATR as % of 20-day average)
- S1/R1 Level: Nearest support (S1) and resistance (R1) zone
- D1 Open/High/Low/Close: Daily price data (Close = current price)

Goal:
Find up to 5 interesting Buy or Sell setups based on the following criteria:
- FXP Delta shows consistent direction across all analysis periods
- Net Long Volume Delta aligns with the trade direction
- Positive total volume change in at least one currency of the pair
- ATR is below 100%
- Buy trades use S1 as Stop Loss and R1 as Profit Target
- Sell trades use R1 as Stop Loss and S1 as Profit Target
- Risk Reward Ratio greater than 0.5

Please provide:
- Symbol
- Direction (Buy/Sell) with current price (Close), SL and TP
- RRR calculation based on Close relative to SL and TP
- Brief explanation for the setup suggestion

Additionally, please highlight setups that nearly meet the criteria where only a single rule is slightly missed and explain what improvement (e.g., slight change in strength, ATR drop, etc.) would make them a valid trading opportunity.

CSV Format Information:
- Delimiter: semicolon (;)
- Decimal: dot (.)
- Encoding: UTF-8 (no BOM)
- Header row present
- First line is: sep=;